/* Bsr. 1.1: bsr01_ISNUR.c Using if statements, relational operators, and equality operators */ #include <stdio.h> int main() { float A, B, C, besar; printf( "A =" ); scanf( "%f", &A ); printf( "B =" ); scanf( "%f", &B ); printf( "C =" ); scanf( "%f", &C ); if ( A > B ) besar = A; else besar = B; if ( C > besar ) besar = C; printf( "Terbesar = %f", besar ); return 0; } |
| A = 5 B = 15 C = 8 Terbesar = 15 |
Showing posts with label tugas. Show all posts
Showing posts with label tugas. Show all posts
Monday, December 29, 2008
Tugas 6
Labels:
bahasa pemrograman,
komputer,
tugas
Sunday, December 28, 2008
Tugas 3
/* Lat. 0.3: lat03.c Hitungan Pencacahan */ #include <stdio.h> int main() { int C = 0, N = 14; while ( C <= N ) { printf("%d", C); C = C + 2; } printf( "Hitungan Terakhir = %d", C - 2 ); return 0; } |
| 0 2 4 6 8 10 14 Hitungan Terakhir = 14 |
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bahasa pemrograman,
komputer,
tugas
Tugas 5
/* ling 1.1: ling01_ISNUR.c area and round program */ #include <stdio.h> int main() { float r, luas, keliling; printf( "jari-jari = " ); scanf( "%f", &r ); luas = r * r * 3.14; printf( "luas = %f\n", luas ); keliling = 2 * r * 3.14; printf( "keliling = %f\n", keliling ); return 0; } |
| jari-jari = 100 luas = 31400 keliling = 628 |
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bahasa pemrograman,
komputer,
tugas
Tugas 4
/* Lat. 0.4: lat04.c Histogram printing program */ #include <stdio.h> #define SIZE 10 int main() { int n[ SIZE ] = { 19, 3, 15, 7, 11, 9, 13, 5, 17, 1 }; int i, j; printf( "%s%13s%17s\n", "Element", "Value", "Histogram" ); for ( i = 0; i <= SIZE-1; i++ ) { printf( "%7d%13d ", i, n[ i ]); for ( j = 1; j <= n[i]; j++ ) printf( "%c", '*' ); printf( "\n"); } return 0; } |
| Hasil | |
|---|---|
| 19 | ******************* |
| 3 | *** |
| 15 | *************** |
| 7 | ******* |
| 11 | *********** |
| 9 | ********* |
| 13 | ************* |
| 5 | ***** |
| 17 | ***************** |
| 1 | * |
Labels:
bahasa pemrograman,
komputer,
tugas
Tugas 2
/* Lat. 0.2: lat02.c Hitungan Pencacahan */ #include <stdio.h> int main() { int C = 0, N = 6, D = 1; while ( C <= N ) { printf( "%d", D ); D = C + D; } printf( "Hitungan Terakhir = %d", D - 7 ); return 0; } |
| 1 3 6 10 15 21 Hitungan Terakhir = 21 |
Labels:
bahasa pemrograman,
komputer,
tugas
Tugas 1
/* Lat. 0.1: lat01.c Hitungan Pencacahan */ #include <stdio.h> int main() { int C = 2, N = 12; while ( C <= N ) { printf("%d", C); C = C + 2; } printf( "Hitungan Terakhir = %d", C - 2 ); return 0; } |
| 2 4 6 8 10 12 Hitungan Terakhir = 12 |
Labels:
bahasa pemrograman,
komputer,
tugas
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